Cannot convert from string to url in swift 3

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August undefined, 2024

Web1 hour ago · UIScrollView cannot display image either in Portrait or Landscape mode 28 AVAssetExportSession export fails non-deterministically with error: "Operation Stopped, NSLocalizedFailureReason=The video could not be composed." WebUse let fileUrl = URL (fileURLWithPath: filePath) instead. @natev not if the fileURL string contains the scheme "file://" as well if it was obtained using absoluteString instead of the path property. To Convert file path in String to NSURL, observe the following code. …

Cannot convert return expression of type

WebDec 1, 2024 · 3 to convert url to string use this var myurl: NSURL var urlString: String = myurl.absoluteString hope it helps Share Improve this answer Follow answered Dec 3, 2024 at 12:05 Wassim Ben Hssen 509 6 22 I have to modify to urlString = (strurl as AnyObject).absoluteString! – Antonio Abrantes Dec 6, 2024 at 1:20 Add a comment 3 Web3 Answers Sorted by: 12 This is not possible, because a StaticString is defined as A simple string designed to represent text that is "knowable at compile-time". ( Reference) String concatenation happens at runtime. I don't know what you are planing to do, but you can do something like that: flutter easypopup

swift - Using videoComposition breaks export second time (The …

WebMar 26, 2014 · Try in this way. NSURL *fileURL = [ [NSURL alloc] initFileURLWithPath:filePath]; //OR ... Use ` + [NSURL fileURLWithPath:] OR take a look at NSURL Class Reference Hope it helps you. Share Improve this answer Follow answered Mar 26, 2014 at 5:48 Vidhyanand 993 10 21 Add a comment Your Answer WebNote that using NSData (contentsOf: url! as URL) (or Data (contentsOf:) in Swift 3) is a bad idea. That's a synchronous call, and will freeze the UI until it complete. You should really rewrite this to use NSURLSession. – Duncan C Jan 16, 2024 at 19:00 2 I'm having a hard time understanding why this was voted down. WebMay 3, 2024 · results in error: cannot convert value of type 'String' to expected argument type 'Character' I also tried creating a character variable var selectedChar:Character = selectedLetter but I get a conversion error: error: cannot convert value of type 'String?' to specified type 'Character' green gummy oval snacks

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[Solved] How to convert this var string to URL in Swift

Web4 hours ago · Convert Int to String in Swift. 576 Any way to replace characters on Swift String? 277 Swift apply .uppercaseString to only the first letter of a string ... To subscribe to this RSS feed, copy and paste this URL into your RSS reader. Stack Overflow. Questions; Help; Products. Teams; Advertising; Collectives; Talent; WebAug 28, 2024 · I know there are many solutions around related to converting an Image string into data and to set the image in an ImageView. But unfortunately, nothing worked in my case. I have a parsed JSON field which returns an Image as a string. So I'm trying to convert that String as URL and then to get URL data to display the image. green guru backpacksWebApr 21, 2024 · Converting a URL into a String A URL can also be converted into a String by using the absoluteString property: print( … flutter dynamic to map

"WebJul 23, 2024 · You need to call the Instance Property absoluteString in order to retrieve the URL string. Change self.sendDatatoDatabase (photoUrl: url) to guard let url = url else {return} self.sendDatatoDatabase (photoUrl: url.absoluteString) it will make you avoid to force unwrap Share Improve this answer Follow answered Jul 24, 2024 at 4:41 Soren … " - Cannot convert from string to url in swift 3

Cannot convert from string to url in swift 3

Convert Data to String in Swift 3 - Stack Overflow

WebOct 7, 2024 · For that kind of URLs, having to deal with optionals all over our code base is a bit unnecessary, so let's take a look at how we can add a separate way of constructing … WebMar 22, 2024 · 1 Answer Sorted by: 0 When you return in a closure, you are not returning the function getMachineName, you are returning the closure itself. Note that the closure is defined to have type ( [MachineDetails]? , Error?) -> Void, meaning once it is called, you won't be returning in the closure.

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WebJan 28, 2024 · Cannot convert value of type 'String' to expected argument type 'URLSession' Ask Question Asked 4 years, 2 months ago Modified 4 years, 2 months ago Viewed 2k times 0 I use Alamofire 4.0, Swift 4.2 and Xcode 10.2 to request Http Api I have url constant: let weatherUrl = "http://api.openweathermap.org/data/2.5/weather" And … WebJun 14, 2024 · class func persistentFileURL(_ name: String, enclosingDirectoryName: String) -> Foundation.URL { let directoryURL = self.directoryForPersistentStorage(enclosingDirectoryName) let urlPath = directoryURL.path let filePath: NSManagedObjectContext = (urlPath as …

WebAfter migrating to Swift 3 you may need to add appropriate generic parameters for them. If you implement an optional Objective-C protocol requirement in a subclass of a class that declares conformance, you’ll see a warning, “Instance method ‘…’ nearly matches optional requirement ‘…’ of protocol ‘…’”. Workaround: Add an ... WebMar 28, 2024 · Use the String method addingPercentEncoding (withAllowedCharacters:) to URL encode a string directly: var decoded = "url components" var encoded = decoded.addingPercentEncoding( withAllowedCharacters: .urlQueryAllowed ) // encoded is "url%20components" URL Property Examples URLs and Strings

Webinit(fileURLWithPath: String) Initializes a newly created NSURL referencing the local file or directory at path. class func fileURL(withPathComponents: [String]) -> URL? Initializes and returns a newly created NSURL object as a file URL with specified path components. init(resolvingAliasFileAt: URL, options: NSURL.BookmarkResolutionOptions) WebThe corresponding method on URL, checkResourceIsReachable, uses the error-handling mechanism as expected.&26613405. The Swift 3 migrator is conservative and will …

WebNov 1, 2016 · This way you don't need to convert a path to an URL, because you're using an URL from the beginning, and you can handle errors. In your specific case, you will know if your asset is there and if your URL is correct. Share Improve this answer Follow edited Nov 1, 2016 at 15:01 answered Nov 1, 2016 at 14:55 Eric Aya 69.2k 35 179 250 Add a …

WebOct 27, 2016 · 23. How could we convert anyobject to string in swift 3, it's very easy in the older version by using. var str = toString (AnyObject) I tried String (AnyObject) but the output is always optional, even when i'm sure that AnyObject is not a optional value. ios. green gutters and downspoutsWebMay 28, 2024 · If you want to get the best conversion possible, you need to use Foundation’s StringTransform type then call applyingTransform () on your string. You … flutter easyrefresh listviewWebJun 19, 2024 · It appears that your getScreenShotDirectory () method is already a URL. So you get the error trying to pass a URL to the URL (string:) method which, of course, expects a String, not a URL. The simple solution is to properly convert the URL to a path string: let pathURL = getScreenShotDirectory () // URL let pathString = pathURL.path // String Share flutter easyrefresh.builder flutter easyrefresh emptywidgetWebSep 29, 2014 · The reason why you can't do that is because String doesn't have an initializer accepting a double or a float, whereas it implements initializers for all integer types (Int, Uint, Int32, etc.). So @derdida's solution is the right way to do it. I discourage using the description property. green gut glow bundleWebIn Swift 3, the answer appears to have changed. Now, you want to use the String initializer init (describing:) Or, to use the code from the question: result = single_result.valueForKey ("Level") let resultString = String (describing: result) Note that usually you don't want valueForKey. That is a KVO method that will only work on NSObjects. flutter easy localizationWebSep 12, 2016 · You can use the Foundation framework’s JSONSerialization class to convert JSON into Swift data types like Dictionary, Array, String, Number, and Bool. However, because you can’t be sure of the structure or values of JSON your app receives, it can be challenging to deserialize model objects correctly. flutter easy_refresh header